A circle has radius 7 cm. Find circumference and area using π ≈ 22/7.
- Circumference = 2 × 22/7 × 7 = 44 cm.
- Area = 22/7 × 7 × 7 = 154 cm².
- The answers have different units because one measures around and the other inside.
Grade 7 · Maths
A circular garden needs edging around it and grass inside it. These are two different measurements, even though they describe the same circle.
Circumference is the distance around a circle: C = 2πr = πd. Area is the space inside: A = πr². The diameter d is twice the radius r.
Before you start: Radius, diameter, multiplication and square units.
To put ribbon around a circular card, measure its boundary: circumference. To cover its face with coloured paper, measure the inside region: area. A diagram can show both, but they are not interchangeable. A 44 cm length of ribbon cannot be described as 44 square centimetres.
The radius is a line segment from the centre to the circle. A diameter passes through the centre and joins two points on the circle, so d=2r. A line that crosses the circle away from the centre is a chord; it is not necessarily a diameter.
| Known measure | Circumference | Area |
|---|---|---|
| Radius r | 2πr | πr² |
| Diameter d | πd | π(d/2)² |
| r = 7 cm, π ≈ 22/7 | 44 cm | 154 cm² |
| d = 10 cm, exact | 10π cm | 25π cm² |
For every circle, circumference divided by diameter is the same constant, π. That relationship gives C=πd=2πr. The area formula πr² can be understood by dividing a circle into many narrow sectors and arranging them alternately. Their approximate base is half the circumference, πr, and their height approaches r; base times height approaches πr².
This rearrangement explains why squaring the radius matters. Doubling all lengths doubles the circumference, but covers four times the area. Think of scaling a small circular mat into a larger one: both horizontal and vertical dimensions grow.
For radius 3 cm, 6π cm is an exact circumference. Using π≈3.14 gives 18.84 cm; using a calculator’s π gives a slightly different decimal. Follow the question’s instruction and round at the end. The fraction 22/7 is an approximation to π, even when its use makes the arithmetic convenient.
If given area 49π cm², solve r²=49 and choose r=7 cm because radius is positive. If given circumference 18π cm, solve 2r=18 to get r=9 cm. Do not take a square root for circumference; the two formulas have different structures.
A semicircle has half the area of the full circle. Its curved edge is half the circumference, but its complete perimeter also includes the straight diameter. For radius 7 cm and π≈22/7, the curve is 22 cm and the diameter is 14 cm, so the full boundary is 36 cm.
For a circular path around a garden, the path’s area is the area of the outer circle minus that of the inner circle. Draw and label both radii first. The width of the path is added to the radius, not to the diameter.
Attempt a short group of questions before opening the solutions. Use a drawing or written method where helpful. Explain the answer, then try a similar question with a detail changed.
4 m
Radius is half the diameter.
6π cm
Use 2πr.
16π cm²
Square the radius, then multiply by π.
It becomes four times as large
(2r)² = 4r².
18.84 m
Edging is circumference: πd.
14π cm
C=πd.
49π cm²
Radius is 7 cm, so A=π×7².
10 m
2πr=20π.
18 cm
Radius is 9 cm; double it.
9
(3r)²=9r².
4π+8 cm
Half the circumference plus diameter.
16π cm²
25π−9π=16π.
Covering
Fencing uses length; covering uses area.
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